Non- Verbal Reasoning|| Chapter 2: Calendar
📝 Non- Verbal Reasoning:
Non-verbal reasoning hian thil hmuh theihte hriatthiam leh zirchian thiamna te, milemte her kual leh siamrem thiamna te, leh thil inzawmna leh an kalphung (patterns) hriat hran thiamna te a sawifiah a ni.
He bung hi inelna exam (competitive exams) hrang hrangah hmuh tur a awm fo a; hmunhma hriatna (spatial awareness), rilru dik leh felfai taka hman thiamna (logical thinking), leh thil thlir thiamna (observation skills) te fiah nan a pawimawh hle.
Types of Non-Verbal Reasoning:
1. Assemble Image
2. Completion of Incomplete Pattern
3. Hidden Image
4. Mirror Image
5. Water Image
6. Cube and Dice
7. Paper Folding and Cutting
8. Counting Figures
9. Dot Section
- Written by: Elisa Lalrinngheta ( Zo Guide)
@Copyright Reserved by the Author
Chapter 2: Calendar
Calendar hi hun chhutna atana hman a ni a, a bik takin ni (days), kar (weeks), thla (months), leh kum (years) te calendar-a a inziah dan tlawhchhana harsatna awmte chinfelna a ni.
Gregorian Calendar hi official-a hman tlanglawn ber a ni.
🕵️Gregorian Calendar Hriatthiamna
🎯Ni (Days): Hun tehna bulpui ber a ni.
🎯Kar (Weeks): Ni khat aia tam, a ruala chhiar luh leh kual leh thin a ni.
🎯Thla (Months): Kum khat chhunga hun then hrang hrangte an ni.
🎯Kum (Years): Hun rei tak chhung tehna a ni.
✅ Calendar-a hriattur thil pawimawh zualte:
🎯.Kum Pangngai kalphung (Ordinary Year Rules):
Kum pangngai (ordinary calendar year)-ah chuan ni 365 a awm.
🎯 Leap year-ah ni 366 a awm a, kum li dan zelah a thleng thin. Hei hi kan awmna lei in Ni (Sun) a hel kualnaa hun hman ral, ni tling chiah lo (extra fraction) awm kha siamremna a ni.
✅ Leap Year Kalphung:
Leap year hi kum 4 dan zelah a thleng tlangpui.
🎯 Hriat tur: Kum za bi (century years) 100-a sem theih zawng zawngte hi leap year an ni vek kher lo; 400-a sem theih an nih tel chauhvin 'leap century years' an ni thei a ni.
✅ Century leh Leap Century Kumte:
Kum 100 hi century (kum zabi) tia koh a ni.
Leap century kum chu 400-a insem bang lo chauh in a ni thei.
Kum pakhat chu a insem theih dan azirin eng anga thliar hran tur nge ni ang han hmuchhuak teh🕵️.
Century Year: Kum 100 chhung hun a entir.
Leap Century Year: 400-a insem bang lo, thil thleng zen zen lo a ni.
🌎 Kum khat a thlate(Months):
Kum khat chhungin thla 12 a awm.
🎯Thla 7-in ni 31 an nei: January, March, May, July, August, October, leh December.
🎯Thla 4-in ni 30 an nei: April, June, September, leh November.
🎯February hian kum pangngaiah ni 28 a nei a, leap year-ah ni 29 a nei thung.
✅ Odd Days Chhiar Dan:
A hrilhfiahna: Odd days chu kar khat tling lo, ni bang awmte sawina a ni. Entirnan, kar tam tak chhungin ni khat emaw ni hnih emaw, kar khat tling lova ni bang a awm chuan, chung chu odd days an ni.
♻️ Chhut dan tur:
1.Ni zawng zawng kha 7-in sem tur: Odd days hriat nan ni awm zat zawng zawng kha 7-in sem tur a ni (kar khat-ah ni 7 a awm vangin).
2.A bang (Remainder) kha zawng chhuak rawh: 7-a i sem hnua a bang kha odd days chu a ni.
• I sem(divide ) hnu a , a bang kha 0 a nih chuan, odd days a awm lo tihna a ni.
• A bang kha 7 aia tlem a nih chuan, chu chu odd days zat chu a ni.
🕵️ For Example:
10 Days 10 ÷ 7 = remainder 3.
So, there are 3 odd days.
🎯 Odd Days in a Year
➤ A normal year has 365 days. When divided by 7, this results in 52 weeks and 1 odd day (365 ÷7= 52 Remainder is 1).
➤ A leap year has 366 days. When divided by 7, it results in 52 weeks and 2 odd days (366 ÷ 7 = 52 Remainder is 2).
These odd days are crucial for determining the day of the week for any given date in the calendar.
Odd days in Each Month:
🎯March: 31 days → 3 odd days ( 31/7 = 3 remainder)
🎯April: 30 days 2 odd days ( 30/7 = 2 remainder)
Here's a summary of odd days for each month based on the total number of days:
January: 31 days→ 3 odd days ( 31/7 = 3 remainder)
February: 28 days 0 odd days ( 28/7 = 0 remainder)
May: 31 days→ 3 odd days ( 31/7 = 3 remainder)
June: 30 days 2 odd days ( 30/7 = 2 remainder)
July: 31 days→ 3 odd days ( 1/7 = 3 remainder)
September: 30 days 2 odd days ( 30/7 = 2 remainder)
October: 31 days 3 odd days ( 31/7 = 3 remainder)
December: 31 days→ 3 odd days ( 31/7 = 3 remainder)
August: 31 days→ 3 odd days ( 1/7 = 3 remainder)
November: 30 days 2 odd days ( 30/7 = 2 remainder)
✅ Odd Days in Century Years:
🎯400 years: 0 odd days (as it contains 100 leap years).
🎯300 years: 1 odd day (due to 75 leap years).
🎯200 years: 3 odd days (with 50 leap years).
🎯100 years: 5 odd days (comprising 24 leap years).
He thliarhran na (classification) hian kum zabi tam tak chhunga 'odd days' (ni bâng) lo pung khawm dan leh chu chuan calendar chhutna a nghawng dan hriatthiamna kawngah min pui a ni.
🕵️ Hriat tur: Odd days chhiar hian calendar nena inkhuichuam thil hrang hrang chhut nan, entirnan—ni bik tana kar ni (day of the week) hriat chhuah nan min pui a ni.
🕵️Codes for the Weekdays:
Sunday: 0
Monday: 1
Tuesday: 2
Wednesday: 3
Thursday: 4
Friday: 5
Saturday: 6
Example:
🕵️Q) If 5th May 2010 is Wednesday, then what will be the day of the week on 5th June 2022?
✅Explanation: Given: 5th May 2010 was Wednesday.
Step 1: Calculate the odd days between years
2010 to 2022 12 Years (9 Ordinary Years and 3 Leap Years).
So, 3 Leap Years have 6 odd days, And, 9 Ordinary Years have 9 odd days.
Total odd days = 6 + 9 = 15. 15 odd days 15/7 = 2 weeks and 1 odd day.
Step 2: Calculate the odd days between Month and date:
Now, the number of days between 5th May 2022 to 5th June 2022 = 26(May) + 5(June) = 31 days. = 31 days→ 31/7 = 4 weeks and 3 odd days.
Step 3: Calculate the total odd day:
So, 5th June 2022 will be Thursday + 1 + 3 = Sunday.
✅ Hence, the correct answer is "Sunday".
🕵️Q) If 18th February 2005 falls on Friday then what will be the day on 18th February 2007?
Explanation:
Given: 18th February 2005 is Friday.
Calculation:
There was no leap year between 2005 and 2007.
From 18th February 2005 to 18th February 2007: There were only 2 odd days.
So, 18th February 2007 = Friday + 2 = Sunday.
✅ Hence, the correct answer is "Sunday".
🕵️Q) Which year will have the same calendar as the year 2001?
Explanation: To calculate the repeat year, the sum of the odd days must be 7 or 0.
2002 = 1
2003= 1
20042 (leap year)
2005 = 1
2006 = 1
20071
✅ The sum of the odd days from 2002 to 2007 = 7, So 2007, will have the same calendar as 2001.
🌌☄️Shortcut Method:
2001 Leap Year(2000) + 1, And, it repeats after + 6 years.
2001+6= 2007.
✅ Therefore, 2007 will have the same calendar as 2001.
🕵️Q) The day before yesterday was Wednesday. What day will it be the day after tomorrow?
Explanation: According to the given information:
