Basic Concepts of : Speed, Time and Distance

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📝Chapter 1: Basic Concepts of Time, Speed and Distance 

🤷 INTRODUCTION: He Zirlai ah hian Speed,Time and Distance bulthut hriatthiam na nei tura ziah leh hrilhfiah a ni a, Competitive exam hrang hrang hmachhawn tur te tan tangkai tak anih ngei ka beisei a ni.

      ✍️Written by: Elisa Lalrinngheta [Zo Guide founder, writers, tutor, B.sc(Mathematics), Publisher]

@ Copyright Reserved by the author

       Speed,time leh Distance te hi hna hrang hrang exam na ah chuan chhuak duh pawl tak a ni awm e.A tlangpui hriatthiam nei tur chuan a hnuai ami te hi chhiar rawh le:

  Q. 🤔Eng nge Speed, Time leh Distance chu anih chiah le engtin nge kan zawn chhuah ang?🤷

     ✅Speed (V): Hmun khata atanga hmun dang thlenga object a kal chak dan sawi na hi a ni. Heng hmang hian a Unit kan sawi thin
🤷 km/hr, m/s, etc.

Formula:
✅Time (T): Object-in hmun khat atanga hmun dang thlenga a kal hun chhung sawina a ni. Unit: hour, minute, second, etc.
✅Distance (D): Object-in hmun khata atanga hmun dang thlenga a kal hlat zawng a ni. Unit: km, m, etc.

📝Heng Inlaichinna te hian thiam ngei ngei ang che:
D = V × T
V = D / T
T = D / V 

✅Quick Revision:

      Hetah hian, D = Hlatzawng, S = Chak zawng, T = Hun 

1.Hun hi a tlangpuiin second (sec), minute (min), emaw darkar (hr) in an teh thin.

2.Hlat zawng  hi a tlangpuiin meter (m), kilometer (km), emaw miles, yards, emaw feet in an teh thin.

3.Chak zawng hi a tlangpuiin km/h, miles/hr, emaw m/sec in an teh thin.

      📝 Heng a hnuaia Conversation te hi thiam chhiang ang che:

📝Hun,Chak zawng(speed) & Hlat zawng(distance ) Inkungkaihna 

        Hlat zawng hi a danglam thei lo(constant) anih Chuan: 

     Tlân châkna/ chak zawng (speed) chu hun nên a inkalh tlat ang distance hi a danglam thei lo anih chuan : 

 SPEED a sân chuan —> Hun a tlem; Speed a tlem chuan —> Hun a tam 
_________________________________________________

✅Speed tih sang(increasing Speed): Speed a sân chuan, distance  thu hmun vawn nan hun a tlem ngei ngei thin a ni. Entir nan, 100 km i tlân a, i tlân châkna 50 km/h atanga 100 km/h a i tihsan chuan, hun i hman tur chu darkar 2 atangin darkar 1-ah a tla hniam daih ang.


✅Speed tih hniam(decreasing speed): Chutih rualin, speed kan tih hniam chuan, distance pawh a tla hniam ang. Darkar 2 chhung tho ah, speed 50 km/h in i tlan chuan, 100 km chauh i cover ang.

Tun ah examples kan lo en ho tawh ang:
.                                                                                   

Q.Entirna 8: Golin-i'n a tlan chak dan pangngai (7/8)-a a tlanin hmun thenkhat a thleng a, a hun hman pangngai aiin minute 20 in a hma zawk. Chu hmun thlen nan chuan a hun hman pangngai zat chhut chhuak rawh.

Ans: 
🤔Chinfel dan:
 Golin-i'n a hun hman pangngai chu T minutes leh a tlan chak dan pangngai chu S ni rawh se.

 Hlat zawng = Tlan chak dan × Hun ( speed×time)

    A tlan chak dan pangngai 7/8 a tlanin, a tlan chak dan chu 7/8 S a ni a, a hun hman chu (T+20) minutes a ni. 

✅ Hmanrua:
 Hlat zawng pangngai a thlen = Hlat zawng tlan chak dan tih hniam a thlen 

 Given: 
Golin-i'n a tlan chak dan pangngai (7/8)-a a tlanin hmun thenkhat a thleng a, a hun hman pangngai aiin minute 20 in a thleng hma zawk. 

🤔 Concept: Golin-i'n a hun hman pangngai chu T minutes leh a tlan chak dan pangngai chu S ni rawh se. 

Hlat zawng = Tlan chak dan × Hun

        A tlan chak dan pangngai (7/8)-a a tlanin, a tlan chak dan chu (7/8)S a ni a, a hun hman chu (T+20) minutes a ni. 

 Hmanrua: 
 Hlat zawng pangngai a thlen = Hlat zawng tlan chak dan tih hniam a thlen .

Chhut chhuah dan:

➡️ S× T=(7/8)S × (T+20)

S leh  S chu RHS leh LHS lam ve ve a, a awm avangin an in cancel out ang a, S a awm tawh lo ang
 
 T=(7/8) × (T+20)

               8T= 7(T+20)=7T + 140

➡️8T-7T= 140

➡️T= 140

Ans: 140 Minutes 
                                                                                     
Example 6: The ratio of the time taken by Caro and David to cover a distance of 1000 km is 13 21. Find the ratio of their speeds.

Ans: 
. 
                                                                                 
Example 8: Ram is at A and Shyam is at B. They proceed towards each other simultaneously. After meeting each other in the way, Ram takes 2 h to reach B and Shyam takes 8 h to reach A. If the speed of Ram is 40 km/h, the speed of Shyam is:

✅Solution:
Given:
Speed of Ram = 40 km/hour
Time taken by Ram to reach B = 2 hours
Time taken by Shyam to reach A = 8 hours

🤔Formula Used:
Distance = Speed x Time

Speed of Ram/Speed of Shyam = √(Time of Shyam/Time taken by Ram)

Solution:
Speed of Shyam = b km/h
Speed of Ram/Speed of Shyam = √(Time of Shyam/Time taken by Ram)

40/b = √(8/2)
⇒40/b = 2
b = 20 km/hour

Hence, The correct answer is 20 km/hour.

                   Thank you 😊.                          

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